Answer:
Explanation:
We shall find the solution of this problem with the help of vector notation of i , j , which show east and north direction .
The first displacement can be represented by the following
D₁ = - 3 cos 45 i + 3 sin45 j = - 3 / √2 i + 3 / √2 j
The second displacement can be represented by the following
D₂ = - 5 cos 45 i - 5 sin45 j = - 5 /√2 i - 5 /√2 j
The third displacement can be represented by the following
D₃ = 4 cos 45 i + 4 sin45 j = 4 /√2 i + 4 /√2 j
Total displacement D =
D₁ +D₂ + D₃
= i ( -3 -5 + 4 ) / √2 + j ( 3 - 5 + 4 ) / √2 j
= - 4 / √2 i + 2 / √2 j
D = - 2.8288 i + 1.414 j
Magnitude of D
= √ ( 2.8288² + 1.414² )
= 3.16 miles
For direction we calculate angle with X axis
Tanθ = 1.414 / 2.8288
θ = 26 °
As x is negative and Y is positive ,
the direction will be north of west .