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Determining a Number of Solutions

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Determine whether the systems have one solution, no solution, or infinitely many solutions.


3x - 2y = 3; 6x - 4y = 1


One Solution


No Solution


Infinitely Many Solutions


3x - 5y = 8,5x - 3y = 2


3x + 2y = 8; 4x + 3y = 1


3x - y = 3; 2x - 4y = 2


3x - 4y = 2, 6x - y = 1


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User Yue
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2 Answers

5 votes

Answer:

ONE SOLUTION

3x-5y=8; 5x-3y=2

3x+2y=8; 4x+3y=1

NO SOLUTION

3x-4y=2; 6x-8y=1

3x-2y=3; 6x-4y=1

INFINITELY MANY SOLUTIONS

3x-6y=3; 2x-4y=2

Explanation:

i got this right on edge

User Flygoast
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8.2k points
2 votes

Answer:

No Solution

Explanation:

For one solution;

it will be consistent and independent ( example, x = 1 and y = 2)

For no solution;

it will be inconsistent and independent ( example, 0 = 2)

For many solution;

it will be consistent and dependent ( example, 1 = 1, 2 = 2, y = y, x = x)

Given;

3x - 2y = 3 -------------- equation (1)

6x - 4y = 1 --------------- equation (2)

6: 18x - 12y = 18 -------------equation (3)

3: 18x - 12y = 3 --------------- equation (4), subtract (4) from (3)

--------------------------------------------

0 - 0 = 15

-----------------------------------------------

0 = 15

The solution is inconsistent and independent, because zero (0) cannot be equal to 15

Thus, the system has no solution

User Zing Lee
by
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