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A bar slides vertically between two conducting rails without friction in a magnetic field. The rails are connected via a resistor. The bar reaches a constant velocity and slides for 2m. How much energy is dissipated in the resistor during these 2m's

User Lumpy
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1 Answer

1 vote

Answer:

The energy dissipated is
E = 9.8 J

Step-by-step explanation:

From the question we are told that

The distance covered at constant velocity d = 2 m

The velocity is
v = 1.5 \ m/s

Generally at constant velocity the magnetic force on the bar is mathematically represented as


F = m * g

substituting values


F = 0.5 * 9.8


F = 4.9 \ N

The energy dissipated is mathematically evaluate as


E = F * d

substituting the value


E = 4.9 * 2


E = 9.8 J

User SurvivalMachine
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