Question

An object is held 24.8 cm from a lens of focal length 16.0 cm. What is the magnification of the image?

Answer 1

The answer that my online curriculum said was correct was: —1.81

Answer 2

Magnification is 1.8

Step-by-step explanation:

Given data

object distance u = 24.8 cm

focal length f= 16 cm

image distance v= ?

In other to solve for the magnification we have to solve for the image distance

The mirror formula is

`(1)/(v) +(1)/(u)= (1)/(f) \\`

Substituting we have

`(1)/(v) +(1)/(24.8)= (1)/(16) \\\\(1)/(v)= (1)/(16) -(1)/(24.8)\\\\(1)/(v)=(24.8-16)/(396.8)= (8.8)/(396.8)= (1)/(45)\\\\v= 45cm`

The magnification is

`m= (v)/(u)\\\m= (45)/(24.8)\\\\m= 1.8`