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3 votes
Solve the following system of equations.

3x+2y-5=0
x=y+10

User Gusaki
by
7.9k points

2 Answers

3 votes

Answer:Answer:

x = 5 and y = -5

Explanation:

You can use algebra or graphing to solve this. I will be using algebra, with substitution.

Step 1: Move the 5 over in the 1st equation

3x + 2y = 5

x = y + 10

Step 2: Substitute in x

3(y + 10) + 2y = 5

Step 3: Distribute

3y + 30 + 2y = 5

Step 4: Combine like terms

5y + 30 = 5

Step 5: Move the 30 over

5y = -25

Step 6: Divide both sides by 5

y = -5

Step 7: Plug it back in into an original equation to find x

x = -5 + 10

x = 5

Explanation:

User Dalibor Frivaldsky
by
8.7k points
3 votes

Answer:

x = 5 and y = -5

Explanation:

You can use algebra or graphing to solve this. I will be using algebra, with substitution.

Step 1: Move the 5 over in the 1st equation

3x + 2y = 5

x = y + 10

Step 2: Substitute in x

3(y + 10) + 2y = 5

Step 3: Distribute

3y + 30 + 2y = 5

Step 4: Combine like terms

5y + 30 = 5

Step 5: Move the 30 over

5y = -25

Step 6: Divide both sides by 5

y = -5

Step 7: Plug it back in into an original equation to find x

x = -5 + 10

x = 5

User Mockobject
by
8.2k points

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