Question

Quadrilateral FGHJ is dilated according to the rule DO,Two-thirds(x,y)(two-thirds x, two-thirds y) to create the image quadrilateral F'G'H'J', which is not shown. On a coordinate plane, quadrilateral F G H J has points (negative 5, negative 4), (negative 3, negative 2), (negative 1, negative 4), (negative 3, negative 6). What are the coordinates of point J'? (-2,-4) (-2,-6) (Negative nine-halves, negative 4) (Negative nine-halves, negative 9)

Answer 1

(-2, -4)

Explanation:

J = (-3, -6)

J' = 2/3(-3, -6)

J' = (-2, -4)

Answer 2

J' = (-2, -4)

Explanation:

It appears that point J is (-3, -6). The dilation by 2/3 about the origin causes each of these coordinates to be multiplied by 2/3:

J' = ((2/3)(-3), (2/3)(-6))

J' = (-2, -4)