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Z^2 + 11z+ 28 find the factor of polynomial

User Armin
by
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1 Answer

4 votes

Answer:

(z+7)*(z+4)

Explanation:

The first term is, z2 its coefficient is 1 .

The middle term is, +11z its coefficient is 11 .

The last term, "the constant", is +28

Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28

Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is 11 .

-28 + -1 = -29

-14 + -2 = -16

-7 + -4 = -11

-4 + -7 = -11

-2 + -14 = -16

-1 + -28 = -29

1 + 28 = 29

2 + 14 = 16

4 + 7 = 11 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 4 and 7

z2 + 4z + 7z + 28

Step-4 : Add up the first 2 terms, pulling out like factors :

z • (z+4)

Add up the last 2 terms, pulling out common factors :

7 • (z+4)

Step-5 : Add up the four terms of step 4 :

(z+7) • (z+4)

Which is the desired factorization

User Twotwotwo
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