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A length of nickel wire is subjected to a tension of 821 N. Determine the radius of the wire used if the wave speed of transverse waves moving along this wire is 185 m/s. Take the density of nickel to be 8.90 ✕ 103 kg/m3.

User Guiomie
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1 Answer

3 votes

Answer:

r = 9.27*10^-4m

Step-by-step explanation:

Given the following parameters;

Tension in the wire T = 821N

wave speed of the transverse wave v = 185m/s

density of nickel = 8.9*10³kg/m³

radius of the wire = ?

Using the relationship for finding the speed of the wave to first get the linear density;


v = \sqrt{(T)/(\mu) } where
\mu is the linear density


185 = \sqrt{(821)/(\mu) }\\185^(2) = (821)/(\mu) \\\mu = (821)/(185^(2) )\\\mu = 0.024kg/m

Also;


\mu = mass m/Length L

Since mass m = density
\rho * volume
V


\mu = (\rho V)/(L)


\mu = (\rho AL)/(L)\\\mu = \rho A

Since A = area of the wire =
\pi r^(2)


\mu = \rho \pi r^(2)

Given
\mu = 0.024kg/m \ and\ \rho = 8.9*10^(3)kg/m^(3)

0.024 = 8.9*10³*3.14r²

0.024 = 27.946r²

r² = 0.024/27.964

r² = 8.6*10^-7

r =√8.6*10^-7

r = 9.27*10^-4m

Radius of the wire is 9.27*10^-4m

User Ashrugger
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