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A mountain bike tire completes 20 revolutions and travels 136 feet. Rounded to the nearest inch, what is the diameter of the bike’s tire? use 3.14

1 Answer

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Answer:

26 inches

Explanation:

The bike tire moves 136 feet in 20 revolutions.

The tire is shaped as a circle. 1 revolution is equivalent to going round the circumference 1 time, hence, the circumference of the bike tire is:

136/20 = 6.8 feet

The circumference of a circle is given as:

C = πD

=> D = C / π

Therefore, the diameter of the bike tire is:

D = 6.8 / 3.14 = 2.17 feet

To convert to inches:

1 feet = 12 inches

2.17 feet = 2.17 * 12 = 26.04 inches ≅ 26 inches

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