Question

Which shows the equation below written in standard form?

11 - 4x = (3x-2)2 + 1
A. 9x2-16x-6 = 0
B. 972-8x + 16 = 0
C. 92-16x+ 16 = 0
D. 92-8x-6=0

Answer 1

Explanation:

Given that,

An equation
`11-4x=(3x-2)^2+1` in the standard form.

Solution,

`11-4x=(3x-2)^2+1`

=
`11-4x=9x^2+4-12x+1\ \ \ [(a-b)^2=a^2+b^2-2ab]`

`11-4x=9x^2+4-12x+1\\\\11-4-1=9x^2-12x+4x\\\\6=9x^2-8x\\\\=9x^2-8x-6=0`

So, the standard form is given by option (D).