Answer:
The new period of rotation using the new spring would be less than the period of rotation using the original spring
Step-by-step explanation:
Generally the period of rotation of the mass is mathematically represented as
![T = 2 \pi \sqrt{(I)/(k) }](https://img.qammunity.org/2021/formulas/physics/college/6p6w43mqs72y7fu7kxvflsotar0bhdck8r.png)
Here I is the moment of inertia of the mass about the rotation axis and k is the spring constant
Now looking at the equation we can tell that T is inversely proportional to the square root of the spring constant which means that for a larger spring constant the time period would be lesser