Answer:
% loss =K_{f} / K₀ 100 =% 75%
Step-by-step explanation:
This is a problem that we can solve using the conservation of the moment.
We define a system formed by the car plus the moose, so that the outside during the crash have been internal and the moment is preserved.
Initial moment. Before the crash
p₀ = M v₁
Final moment. After the crash
= (M + m) v
where M and m are the mass of the carra and the moose, respectively
p₀ = p_{f}
M v₁ = (M + m) v
v = M / (M + m) v₁
now we can calculate the kinetic energy
before the crash
K₀ = ½ M v₁²
after the crash
K_{f} = ½ (M + m) v²
K_{f} = ½ (M + m) (M / (M + m) v1)²
K_{f} = ½ M² / (M + m) v₁²
In order to find a loss of energy, let's look for the relationship between the magnitudes
% loss =K_{f} / K₀ 100
% loss = (½ M² / (M + m) v₁²) / ½ M v₁² 100
% loss = M / (M + m) 100
% loss = 1 / (1 + m / M) 100
% loss = 1 / (1 + 500/1500) 100
% loss = 75%