Answer:
Ninety percent of all students at private universities pay less than $25,807.
Explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 20207, \sigma = 4375](https://img.qammunity.org/2021/formulas/mathematics/college/egjhzyka1s7bgf5la3e5c2r5altf3fd7ct.png)
Ninety percent of all students at private universities pay less than what amount
Less than the 90th percentile, which is X when Z has a pvalue of 0.9. So X when Z = 1.28.
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
![1.28 = (X - 20207)/(4375)](https://img.qammunity.org/2021/formulas/mathematics/college/jatgum1nz8obgjx0xoe1bvqrifkp2kdr7f.png)
![X - 20207 = 1.28*4375](https://img.qammunity.org/2021/formulas/mathematics/college/9y5pna3idfabgnuj27gluh2n775ei46z21.png)
![X = 25807](https://img.qammunity.org/2021/formulas/mathematics/college/d4wa2krzimu09s7q73v2eqfpy8s1rdwfut.png)
Ninety percent of all students at private universities pay less than $25,807.