Answer:
X = 27.86°C
Y = 26.11°C
Step-by-step explanation:
Hello,
To solve this question, we'll need to relate heat energy with specific heat capacity
Q = mc∇T
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇T = T2 - T1 = change in temperature of the substance.
For X,
Q = mc∇T
Assuming m = 1 g and Q = 1J
T = 25°C
Q = mc(T2 - T1)
1 = 1 × 0.350 × (T2 - 25)
1 = 0.350T2 - 8.75
8.75 + 1 = 0.350T2
Solve for T2
T2 = 9.75 / 0.350
T2 = 27.86°C
For Z
Assuming Q = 1J and M = 1g
Q = mc∇T
Q = mc(T2 - T1)
1 = 1 × 0.895 (T2 - 25)
1 = 0.895T2 - 22.375
22.375 + 1 = 0.895T2
23.375 = 0.895T2
Solve for T2
T2 = 23.375 / 0.895
T2 = 26.11°C
Since both X and Z have equal mass and same energy was passed through them, the final temperature of X = 27.86°C and Z = 26.11°C
As a general observation, whenever comparing two specific heat capacities of different metals, the metal with the greater value of specific heat capacity would have the lower final temperature while the metal with the lower specific heat capacity would have the higher temperature.