Question

The sum of four consecutive integers is 266. What are the integers?

Answer 1

The 4 consecutive integers are 65,66,67,68

Explanation:

Ok so there are 4 different numbers and they are consecutive, so you'd start of like:

266= n+(n+1)+(n+2)+(n+3). Next you would collect like terms to simplify..

266=4n+6. Next you want to solve for n...

266-6=4n+6-6

260=4n

260/4=4n/4

65=n....so you have n.hurray, but you need the other three numbers..so just substitute 65 as n in the formula:

266=65+(65+1)+(65+2)+(65+3)

266=65+66+67+68

266=266 both sides are equal so it means the equation is solved. The 4 consecutive integers are 65,66,67,68

Answer 2

Let the four consecutive integers are x,x + 1,x + 2,x + 3.

According to the question,

Sum of four consecutive integers = 266. [ Given ]

⇒ x + x + 1 + x + 2 + x + 3 = 266

⇒ 4x + 6 = 266

⇒ 4x = 260

⇒ x = 260/4

⇒ x = 65

Integers are:

• x = 65

• x + 1 = 65 + 1 = 66

• x + 2 = 65 + 2 = 67

• x + 3 = 65 + 3 = 68