Answer:
The situation per week is 30 + 6n
where n is the number of weeks
Range of the function is 18 for the first four weeks of data
Explanation:
Here, we are to use an arithmetic sequence for a representation.
The first term here is a which is 30 clients while the common difference of d is 6 new clients per week
So we can write the nth term of the sequence as;
Tn = a + (n-1)d
Tn = 30 + (n-1)6
Tn = 30+ 6n -6
Tn = 24 + 6n
where n is the number of weeks
Now for the second week we shall have a total of a+ d clients = 30 + 6 = 36
For the third we have 24 + 6(3) = 24 + 18 = 42
For the fourth, we have 24 + 6(4) = 24 + 24 = 48
Thus the range mathematically means the difference between the highest and lowest for that four weeks = 48-30 = 18