Answer:
The ratios must be 88% of grade A sugar and 12% of grade B sugar.
Explanation:
On the grade A every kg costs £75, while on the grade B every kg costs £50. The final mixture we want to make needs to cost £72 per kg. We will sum a certain mass of grade A, "x", with a certain mass of grade B, "y". The sum of these masses must be equal to 1 kg. So we have:
![x + y = 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/d12t7pn279s5if1jsz8o956jah2sesmvb5.png)
Since we want the final mixture to cost £72, we need to satisfy:
![75*x+ 50*y = 72](https://img.qammunity.org/2021/formulas/mathematics/high-school/gihzezq5dxfemxcrsnyyiuuvnf24sei8ie.png)
Solving the system of equation will reveal the ration that must be used.
![\left \{ {{x + y=1} \atop {75*x + 50*y=72}} \right.\\ \left \{ {{-50*x + -50*y=-50} \atop {75*x + 50*y=72}} \right.\\25*x = 22\\x = (22)/(25) = 0.88\\y + x = 1\\y = 1 - x \\y = 1 - 0.88 = 0.12](https://img.qammunity.org/2021/formulas/mathematics/high-school/7hn72ae6ikungjp1oss5c6ycsfbw5a3z4s.png)
The ratios must be 88% of grade A sugar and 12% of grade B sugar.