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URGENT A 69.5 kg runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the track is 28.2 m, what is the centripetal force needed to keep the runner in circular motion? DO NOT ANSWER WITH CENTRIPETAL ACCELERATION I KNOW WHAT IT IS (2.27m/s^2)

User Hermine
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2 Answers

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Answer:

Can an object accelerate if it's moving with constant speed? Yup! Many people find this counter-intuitive at first because they forget that changes in the direction of motion of an object—even if the object is maintaining a constant speed—still count as acceleration.

Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

The figure below shows an object moving in a circular path at constant speed. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation—the center of the circular path. This direction is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration a_ca

c

a, start subscript, c, end subscript; centripetal means “toward the center” or “center seeking”.

Step-by-step explanation:

User WynandB
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6 votes

Answer:

SO THE CENTRIPETAL FORCE IS 158N

Step-by-step explanation:

m=69.5kg

v=8.00m/s

r=28.2m

Fc=?

as we know that

Fc=mv²/r

putting values

Fc=69.5kg×(8.00m/s)²/28.2m

Fc=(69.5kg×64m²/s²)/28.2m

Fc=(4448kgm²/s²)/28.2m

Fc=157.7N≈158N

User Grant Clements
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