Answer:
To be dropped, the client must have debts of $949.40 or lower.
Explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
![\mu = 3027, \sigma = 1060](https://img.qammunity.org/2021/formulas/mathematics/college/e8jacvt8alhljdbfhi3k31n562fv3kswi3.png)
Bottom 2.5%
The 2.5th percentile and lower.
The 2.5th percentile is X when Z has a pvalue of 0.025. So X when Z = -1.96. Then
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
![-1.96 = (X - 3027)/(1060)](https://img.qammunity.org/2021/formulas/mathematics/college/aqu2gvakb52ij5dk615tb9bq4bv1b4o7x6.png)
![X - 3027 = -1.96*1060](https://img.qammunity.org/2021/formulas/mathematics/college/xmzhky1pkj53gfl5qmj7nvkjhh84k482tg.png)
![X = 949.4](https://img.qammunity.org/2021/formulas/mathematics/college/lsv1pyhkbffdjqmb666lhg42aufnryuq2w.png)
To be dropped, the client must have debts of $949.40 or lower.