Question

You wish to make a 0.289 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 100 mL of the dilute solution

Answer 1

`V_1=9.63mL`

Step-by-step explanation:

Hello,

In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:

`n_1=n_2\\`

That in terms of molarities and volumes is:

`M_1V_1=M_2V_2`

Whereas
`M_1` is the initial molarity (3.00 M) of the stock solution,
`M_2` the molarity of the diluted solution (0.289 M),
`V_1` the aliquot of the stock (concentrated) solution and
`V_2` the volume of the diluted solution (100 mL), thus, we compute
`V_1` as required:

`V_1=(M_2V_2)/(M_1) =(0.289M*100mL)/(3.00M) \\\\V_1=9.63mL`

Best regards.