Question

Solve y= ax^s+c for x

Answer 1

`\displaystyle x= \sqrt[s]{(y-c)/(a)}`

Explanation:

`\displaystyle y= ax^s+c`

Subtract
`c` on both sides.

`\displaystyle y-c= ax^s+c-c`

`\displaystyle y-c= ax^s`

Divide
`a` on both sides.

`\displaystyle (y-c)/(a) = (ax^s)/(a)`

`\displaystyle (y-c)/(a) = x^s`

Take the root of
`s` on both sides.

`\displaystyle \sqrt[s]{(y-c)/(a)} =\sqrt[s]{x^s}`

`\displaystyle \sqrt[s]{(y-c)/(a)} =x`

Answer 2

`x= \sqrt[s]{ (y - c)/(a) } \\`

Explanation:

`y = a {x}^(s) + c \\ y - c = a {x}^(s) \\ (y - c)/(a) = \frac{a {x}^(s) }{a} \\ (y - c)/(a) = {x}^(s) \\ \sqrt[s]{ (y - c)/(a) } = \sqrt[s]{ {x}^(s) } \\ x= \sqrt[s]{ (y - c)/(a) }`

hope this helps you