Question

A line is perpendicular to y = 4x – 2

and intersects the point (4, -11).
What is the equation of this
perpendicular line?

Answer 1

`y = (-(1)/(4) )x-10`

Explanation:

Perpendicular => So the slope will be the negative reciprocal of this slope

Slope = m =
`-(1)/(4)`

Point = (x,y) = (4,-11)

So, x = 4, y = -11

Putting this in slope intercept equation to get b

`y = mx +b`

-11 =
`(-(1)/(4) )`(4) + b

-11 = -1 + b

b = -11+1

b = -10

Now putting the slope and y-intercept in the equation to get the required slope intercept equation.

`y = (-(1)/(4) )x-10`