Question

Write an equation of the line containing the point (3,1) and perpendicular to the line 4x−3y=2

Answer 1

y = - 3/4 x + 5/4

Explanation:

4x−3y=2

3y = 4x - 2

y = 4/3 x - 2/3, slope of the given line m = 4/3

Slope of the perpendicular line m = - 3/4.

y = mx + b

y = - 3/4 x + b

Given point of this line (3,1). Using this point we can find b.

1 = - 3/4 * 3 + b

1 = - 1/4 + b

b = 1 + 1/4 = 5/4

y = - 3/4 x + 5/4