Question

To solve 49^3x = 343^2x+1, write each side of the
equation in terms of base
DONE

Answer 1

no solution

Explanation:

49^3x = 343^2x+1

49 = 7^2 and 343 = 7^3

7^2 ^3x = 7^3 ^2x+1

we know that a^b^c = a^ (b*c)

7^(2 *3x) = 7^(3 *(2x+1))

7^(6x) = 7^(6x+3)

The bases are the same so the exponents have to be the same

6x = 6x+3

Subtract 6x from each side

0 =3

This is never true so there is no solution