Question

A softball player moving 3.89 m/s

starts a slide, decelerating at -1.44 m/s2
for 4.80 m. How much time does the
slide take?

Answer 1

1.9

Step-by-step explanation:

I am on acellus and thats the right answer lol

Answer 2

0.119 s

Step-by-step explanation:

Given that

`U=3.89\ m/s\\a=-1.44\ m/s^2\\S=4.8\ m`

Lets take final speed of the softball after covering 4.8 m = V

We know that

`V^2=U^2+2aS\\V^2=3.89^2-2* 1.44* 4.8\\V=3.7\ m/s`

Also We know that

`V=U+at\\`

Putting the value of V ,U and a in the previous equation We get

`3.7=3.89-1.44* t\\t=0.119\ s`

Therefore slide time will be 0.119 s