Question

Use the fundamental identities to verify

Answer 1

See below

Explanation:

`6\cot^2(\gamma)(\sec^2(\gamma)-1)=6\\\\\\\\cot^2(\gamma)(\sec^2(\gamma)-1)=1\\\\\\(\cos^2(\gamma))/(\sin^2(\gamma))\left((1)/(\cos^2(\gamma))-1\right)=1\\\\\\(1)/(\sin^2(\gamma))-(\cos^2(\gamma))/(\sin^2(\gamma))=1 \\\\\\\csc (\gamma) - \cot (\gamma)=1 \\\\\\1=1 \\\\QED`

Hope this helps!

Answer 2

see below

Explanation:

6 cot ^2 (y) ( sec^2 (y) -1) = 6

We know that ( sec^2 (y) -1) = tan ^2(y)

6 cot ^2 (y) tan ^2 (y) = 6

We know cot = cos/ sin and tan = sin / cos

6 cos/ sin ^2 (y) sin/cos ^2 (y) = 6

6 ( 1) = 6

6=6