Answer:
48.00L of CO₂ are formed.
76.00L of O₂ are needed
Step-by-step explanation:
Based on the reaction:
C₆H₁₄ + 19/2O₂ → 6CO₂ + 7H₂O
Where 1 mole of hexane reacts with 19/2 of O₂ to produce 6 moles of CO₂ and 7 moles of H₂O
Using Avogadro's law, volume is directely proportional to moles of gas.
If 1 mole of reaction of hexane is equal to 8.00L, 6 moles of CO₂ that are produced have as volume:
8.00L ₓ 6 =
48.00L of CO₂ are formed.
Again, for a complete burning of hexane, you need 19/2 times of moles of oxygen. As you have 8.00L of hexane, you need:
8.00L × (19/2) =
76.00L of O₂ are needed