Question

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Answer 1

53

Explanation:

Using SOHCAHTOA you already know all three side lengths so you could use sine, cosine, or tangent. I'll solve using sine:

`sinB=(4)/(5)`

Use the inverse of sin to isolate Angle B:

`arcsin(sinB)=arcsin((4)/(5) )`

`B=arcsin((4)/(5) )`

`B=53` when rounded to the nearest degree

Answer 2

m∠B≈53°

Explanation:

Since this is a 3, 4, 5 triangle, the angle measures are:

∠A=36.87°

∠B=53.13°

∠C=90°

m∠B≈53°