Answer:
0.019 L
Step-by-step explanation:
Let the volume coefficient of thermal expansion be γ
γ= 950 × 10-6 K-1
Initial volume V1= 1.00L
Final volume V2= ?????
Initial temperature θ1 = 30°C
Final temperature θ2 = 50°C
From;
γ= V2-V1/V1 (θ2 - θ1)
Making V2 the subject of the formula;
V2= γ V1(θ2 - θ1) + V1
Substituting values;
V2= 950 × 10^-6 × 1.00(50-30) + 1.00
V2= 1.019 L
Change in volume = V2-V1
Therefore change in volume= 1.019 L- 1.00L = 0.019 L