Question

How many molecules of water are proud you was from 19.2 g of O2

Answer 1

Answer : The number of moles of water are,
`3.6* 10^(23)`

Explanation : Given,

Mass of
`O_2` = 19.2 g

Molar mass of
`O_2` = 32 g/mol

The balanced chemical reaction will be:

`H_2+2O_2\rightarrow 2H_2O`

First we have to calculate the moles of
`O_2`.

`\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}`

`\text{Moles of }O_2=(19.2g)/(32g/mol)=0.6mol`

Now we have to calculate the moles of
`H_2O`.

From the balanced chemical reaction, we conclude that:

As, 2 moles of
`O_2` react to give 2 moles of
`H_2O`

So, 0.6 moles of
`O_2` react to give 0.6 moles of
`H_2O`

Now we have to calculate the number of moles of
`H_2O`.

As, 1 mole of
`H_2O` molecule occupies
`6.022* 10^(23)` molecules of
`H_2O`

So, 0.6 mole of
`H_2O` molecule occupies
`0.6* 6.022* 10^(23)=3.6* 10^(23)` molecules of
`H_2O`

Therefore, the number of moles of water are,
`3.6* 10^(23)`