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Determina el valor numérico del polinomio (2x^3y^2z)/3 - 10x^2y^3z^2 + 12 si x = - 2, y = 3 y z = 4

1 Answer

2 votes

Answer:

-2.23007452E187.

Explanation:

Podemos empezar con (2x^ 3y^ 2z) / 3.

x = -2; y = 3; z = 4

2x^3y^2z = (2 * (-2))^ (3 * 3)^ (2 * 4) = (-4)^ 9^ 8 = (-262,144)^ 8 = 22,300,745,200,000,000,000,000,000,000,000,000,000,000,000, que es 2.23007452E43.

2.23007452E43 / 3 = 7.433581733E42.

Segundo, podemos hacer 10x^ 2y^ 3z^ 2.

10x^ 2y^ 3z^ 2 = (10 * (-2))^ (2 * 3)^ (3 * 4)^ 2 = (-20)^ (6)^ (12)^ 2 = 64,000,000^ 12 ^ 2 = 4.722366483E93^ 2 = 2.23007452E187.

Para terminar el problema, lo pondremos todo junto.

7.433581733E42 - 2.23007452E187 + 12 = -2.23007452E187.

Espero que esto ayude!

User Anas Naguib
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