Question

-2[(4y+1)-(2y-2)]=6(7-y)-6​

Answer 1

y=9

Explanation:

-2[(4y+1)-(2y-2)]=6(7-y)-6​

-2[4y+1-2y-2]=6(7-y)-6​

-2[2y-1]=6(7-y)-6​

-2y+2=6(7-y)-6

-2y+2=42-6y-6

Add 6y to both sides

4y+2=42-6

4y+2=38

Subtract 2 from both sides

4y=36

Divide both sides by 4

y=9