Question

The given line segment passes through the points (0, -3) and (-5, -4).

What is the equation of the line that is parallel to the given line and passes through the point (-2, 2)?​

Answer 1

y= 1/5x + 12/5

Explanation:

• Points: (0, -3) and (-5, -4)
• Line: y= mx+b
• Slope: m=(y2-y1)/(x2-x1)= (-4+3)/(-5-0)= -1/-5= 1/5
• Y-intercept: -3= 0*1/5+b ⇒ b= -3
• So the line is: y= 1/5x - 3

Parallel line to this has same slope and passes through the point (-2, 2)

• Its y- intercept is: 2= 1/5(-2)+b ⇒ b= 2+2/5= 12/5

The required equation in slope- intercept form is:

• y= 1/5x + 12/5