Question

Please answer it quickly... i will give brianliest

Q2(i). A line “t” is parallel to 3y = 6x + 9. Find the slope of this line “t”. (ii) Another line “r” is perpendicular to the line 3y = 6x + 9. Find the gradient of the line “r”.

Answer 1

2 and -
`(1)/(2)`

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3y = 6x + 9 ( divide all terms by 3 )

y = 2x + 3 ← in slope- intercept form

with slope m = 2

(i)

Parallel lines have equal slopes, thus

the slope of line t is 2

(ii)

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(2)`, thus

the slope of line r is -
`(1)/(2)`