Question

Activity: A Ferris wheel with a diameter of 60.0 m is moving at a speed of 2.09 m/s. What is the centripetal

acceleration?

Answer 1

Centripetal acceleration of the wheel is
`0.145\ m/s^2`.

Step-by-step explanation:

We have,

Diameter of a Ferris wheel is 60 m

Radius of the wheel is 30 m

Speed of the wheel is 2.09 m/s

It is required to find the centripetal acceleration of the wheel. The formula of centripetal acceleration is given by :

`a=(v^2)/(r)\\\\a=((2.09)^2)/(30)\\\\a=0.145\ m/s^2`

So, the centripetal acceleration of the wheel is
`0.145\ m/s^2`.