Question

Find the solution set for this equation. n^{2} -7n=0

Answer 1

`\boxed{\sf n = 7 \ \ \ \ or \ \ \ \ n = 0}`

Explanation:

`\sf Solution \: set \: for \: equation : \\ \sf n^(2) - 7n = 0 \\ \\ \sf Factor \: n \: from \: the \: left \: hand \: side: \\ \sf n(n - 7) = 0 \\ \\ \sf Split \: into \: two \: equations: \\ \sf n - 7 = 0 \: \: \: \: or \: \: \: \: n = 0 \\ \\ \sf Add \: 7 \: to \: both \: sides: \\ \sf \boxed{ \sf n = 7} \: \: \: \: or \: \: \: \: n = 0`

Answer 2

0 or 7

Explanation:

hello,

we can write the following as n is a common factor

`n^2-7n = n(n-7)`

so

`n^2-7n = 0\\<=> n(n-7)=0\\<=> n = 0 \ or \ n = 7`

hope this helps