Which equation is equivalent to

Question

asked Oct 26, 2021 83.1k views

2 Answers

Jaykumar Patel · Answer 1 · 2021-10-28T10:21:47+0000

Answer:

The answer is option 2.

Explanation:

In the question, 16 and 81 are perfect squares. So in order to find the equivalent equation, you have to factorize it :

APPLY,

$(a + b)(a - b) = {a}^(2) - {b}^(2)$

So for this question :

$16 {x}^(4) - 81 = 0$

${(4 {x}^(2))}^(2) - {(9)}^(2)= 0$

$(4 {x}^(2) + 9)(4 {x}^(2) - 9) = 0$

Ha Nguyen · Answer 2 · 2021-11-01T04:05:08+0000

Answer:

(4x^2 +9)(4x^2-9) =0

Explanation:

16x^4 - 18 = 0

Rewriting

(4x^2)^2 - 9^2 =0

We notice that this is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(4x^2 -9)(4x^2+9) =0