Answer:
Water emerge from the hole at 2.97 m/s
Step-by-step explanation:
There exist and hydrostatic pressure at the base of the trough which is due to force exerted by the water at the top.
Given that the dept of the trough is 0.45 m
g = acceleration due to gravity
v = velocity
Then;
pgh = pv²/2
gh = v²/2
v = √2gh
v = √2*9.81*0.45
v = 2.97 m/s
Velocity of the water is 2.97 m/s