Complete Question
From the mid-1960's to the early 1990's, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in average has a large effect on the tails of the distribution.
Estimate the percentage of students scoring over 700 on 1967.
A 0.7%
B 7%
C 7.67%
D 7.6%
Answer:
The correct option is D
Explanation:
From the question we are told that
The average SAT score in 1967 is
![\= x_1 =543](https://img.qammunity.org/2021/formulas/mathematics/college/c805q7p7w7xmkzagdgzmvimfu7pizs9udl.png)
The standard deviation of score in 1967 is
![\sigma_ 1= 110](https://img.qammunity.org/2021/formulas/mathematics/college/in5436nobs9uev9nx5b06hk6faboye8hm1.png)
The average SAT score in 1994 is
![\= x_2 = 499](https://img.qammunity.org/2021/formulas/mathematics/college/ixlgzfssmc6hdz310olhqybi8q5yz0t73y.png)
The standard deviation of score in 1967 is
![\sigma_ 2 = 110](https://img.qammunity.org/2021/formulas/mathematics/college/rco213foz91shoua7i2zsu68nymqkffj66.png)
The percentage of students scoring over 700 on 1967 is mathematically represented as
![P(X > 700)](https://img.qammunity.org/2021/formulas/mathematics/college/w8ixfqupewjtux8olkxor6zk26mcyc6d7g.png)
Where X is the random variable representing score of student above 700
Now normalizing the above probability we have
![P(X > 700) = P(Z > (700 - \= x_1 )/(\sigma ) )](https://img.qammunity.org/2021/formulas/mathematics/college/igm662liuepiw8v1lbt03g1byuo8dhgc2n.png)
substituting values
![= P(Z > (700 - \= 543)/(110 ) )](https://img.qammunity.org/2021/formulas/mathematics/college/19xxkdcrgakfrlgw8zev8bw775c32bv9y1.png)
![= P(Z > 1.83 )](https://img.qammunity.org/2021/formulas/mathematics/college/lp6m6ltlhpihxb1fzn6vywrdlsnuktq899.png)
Form the normalized z table
= 0.076
= 7.6 %