Question

TotCo is developing a new deluxe baby bassinet. If the length of a newborn baby is normally distributed with a mean of 50 cm and a standard deviation of 5 cm, what should be the interior length of the bassinet to ensure that 99 percent of newborn babies will fit, with a safety margin of 10 cm on each end of the bassinet

Answer 1

The interior length of the bassinet to ensure that 99 percent of newborn babies will fit = 1.7 cm

Step-by-step explanation:

Step-by-step explanation:-

step(i):-

Given mean of population = 50 cm

standard deviation of Population = 5 cm

Given Margin of error = 10 cm

The Margin of error is determined by

`M.E = (Z_(\alpha ) S.D)/(√(n) )`

Step(ii):-

Given level of significance ∝ = 99 % or 1 %

Z₀.₀₁ = 2.576

`10 = (2.576 X 5)/(√(n) )`

`√(n) = (2.576 X 5)/(10)`

√n = 1.3

squaring on both sides , we get

n = 1.69≅ 1.7 cm

Final answer:-

The interior length of the bassinet to ensure that 99 percent of newborn babies will fit = 1.7 cm