Question

What is the energy of light with a wavelength of 652 nm? (The speed of light in a vacuum is 3.00 x 108 m/s, and Planck's constant is 6.626 x 10-34 J·s.)

O A 3.05 x 10-²⁸ j
O B. 3.28 x 10¹⁸ j
O C. 3.05 x 10-¹⁹ j
D. 3.28 x 10²⁷ j

A and C have negative exponents pleas help me​

Answer 1

Option C. 3.05 x 10¯¹⁹ J

Step-by-step explanation:

Step 1:

Data obtained from the question.

wavelength (λ) 652 nm = 652x10^–9m

Velocity of light (v) = 3.00x10^8 m/s

Planck's constant (h) = 6.626x10^-34J·s

Step 2:

Determination of the frequency of the light.

The frequency can be obtained as follow

v = λf

3x10^8 = 652x10^–9 x f

Divide both side by 652x10^–9

f = 3x10^8 / 652x10^–9

f = 4.6x10^14s¯¹

Step 3:

Determination of the energy of the light wave.

This can be obtained as follow:

Planck's constant (h) = 6.626x10^-34J·s

Frequency (f) = 4.6x10^14s¯¹

Energy (E) =..?

E = hf

E = 6.626x10^-34 x 4.6x10^14s¯¹

E = 3.05 x 10¯¹⁹ J

Answer 2

C. 3.05 x 10⁻¹⁹ J

Step-by-step explanation:

Given;

wavelength of the light, λ = 652 nm = 652 x 10⁻⁹ m

speed of light, c = 3.00 x 10⁸ m/s

Planck's constant, h = 6.626 x 10⁻³⁴J·s

Energy of electromagnetic wave is calculated as;

E = hf

where;

f is frequency of the light wave

f = c / λ

`E = hf = h(c)/(\lambda) \\\\E = (hc)/(\lambda) \\\\E = (6.626*10^(-34)*3*10^8)/(652*10^(-9)) \\\\E = 3.05*10^(-19) \ J`

Therefore, the energy of the light is 3.05 x 10⁻¹⁹ J

The correct option is "C"

C. 3.05 x 10⁻¹⁹ J