Question

What is the molarity of 295.0 g of H2SO4 dissolved in 1.500 L of solution?

Answer 1

Answer: 2M

Step-by-step explanation:

Molarity is
`M=(n)/(V)`. It is moles per liters. Since we are given grams, we can convert that to moles by using the molar mass.

`295.0g*(1mol)/(98.079g) =3 mol`

Now that we know the number of moles, we can plug it in and solve for molarity.

`M=(3mol)/(1.5L) =2`