Answer:
Step-by-step explanation:
Hello,
To find the percentage composition of muscovite mica, we'll have to first find the molecular mass of the compound.
Chemical formula = (KF)₂(Al₂O₃)₃(SiO₂)₆(H₂O)
(KF)₂ = 58.097 × 2 = 116.194g/mol
(Al₂O₃)₃ = 3 × 101.96 = 305.88g/mol
(SiO₂)₆ = 6 × 60.08 = 360.48g/mol
H₂O = 18g/mol
(KF)₂(Al₂O₃)₃(SiO₂)₆(H₂O) = 116.194 + 305.88 + 360.48 + 18 = 800.554g/mol
Potassium = (78.18 / 800.554) × 100 = 9.765%
Fluorine = (38 / 800.554) × 100 = 4.75%
Aluminium = (162 / 800.554) × 100 = 20.23%
Silicon = (168.48/800.554) × 100 = 21.04%
Oxygen = (352/800.554) × 100 = 43.97%
Hydrogen = (2 / 800.554) × 100 = 0.24%
Muscovite mica is an aluminosilicate compound or a polysillicate compound found in rocks