Question

4.30 Support for casino in Toronto. In an effort

to seek the public's input on the establishment of a
casino, Toronto's city council enlisted an independent
analytics research company to conduct a public survey.
A random sample of 902 adult Toronto residents were
asked if they support the casino in Toronto. Here are
the results:
Response
Strongly
support
0.16
Somewhat
support
0.26
Mixed
feelings
Probability
?
Response
Somewhat
oppose
0.14
Strongly
oppose
0.36
Don't
know
0.01
Probability
(a) What probability should replace "?" in the distribution?
(b) What is the probability that a randomly chosen adult
Toronto resident supports (strongly or somewhat) a casino?

Answer 1

a) 7% or 0.07

b) 42% or 0.42

Step-by-step explanation:

Let's begin by listing out the given information:

Population = 902,

Probability distribution

Strongly support = 0.16 or 16%,

Somewhat support = 0.26 or 26%,

Mixed feelings = ?,

Somewhat oppose = 0.14 or 14%,

Strongly oppose = 0.36 or 36%

Don't know = 0.01 or 1%

a) The summation of every probability of an event (survey) is 100% ⇒ Pr (survey) = 100%

Pr (survey) = Pr [strongly support + somewhat support + mixed feelings + somewhat oppose + strongly oppose + don't know]

100 = 16 + 26 + x + 14 + 36 + 1

To obtain the probability of the 'Mixed feelings' populace, we subtract the summation of all other probabilities from 1 or 100%

x = 100 - (16 + 26 + 14 +36 + 1) = 100 - 93

x = 7% or 0.07

∴ the probability of the 'Mixed feelings' populace is 7% or 0.07

b) Probability of a random adult supporting is given by the summation of the probabilities of the adults who strongly support & those who somewhat support

Pr (support) = Pr (strongly support) + Pr (somewhat support)

Pr (support) = 0.16 + 0.26

Pr (support) = 0.42 or 42%

∴ the probability that a randomly chosen adult supports the casino in Toronto is 42%