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how mant joules of heat energy must be added to 5 grams of liquid water to change its temperature from 10 degrees celsius ton30 degrees celsius

User Fockus
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2 Answers

9 votes
9 votes
Answer:

418

Step-by-step explanation:

A specific heat of water= 4.18 J/g.k


Q= 10(4.18)(10)

Q= 418 J
User Yordis Prieto Lazo
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22 votes
22 votes
The answer to your question is 418
User Xenep
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