Question

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume of the 1.475 M stock NaOH solution needed to prepare 250.0 mL of 0.1374 M dilute NaOH solution.

Answer 1

`V_1=23.3~mL`

Step-by-step explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

`C_1*V_1=C_2*V_2`

Now we can identify the variables:

`C_1=~1.475_M`

`V_1=~?`

`C_2=~0.1374_M`

`V_2=~250.0~mL`

If we plug all the values into the equation:

`1.475_M*V_1=0.1374_M*250.0~mL`

And we solve for
`V_1`:

`V_1=(0.1374_M*250.0~mL)/(1.475_M)`

`V_1=23.3~mL`

I hope it helps!