Answer:
The frequency shift detected is
Step-by-step explanation:
From the question we are told that
The normal frequency of the state highway patrol radar guns
![f = 8.66 GHz = 8.66 *10^(9) \ Hz](https://img.qammunity.org/2021/formulas/physics/college/9u88bgudozls9tueua8uotj08zqmearqyn.png)
The speed of approach is
![v = 35 .0 \ m/s](https://img.qammunity.org/2021/formulas/physics/college/tjbt9vqx3dsets0ri4zew7yq1oizwpmvnc.png)
Now the frequency measure by the the state highway patrol radar guns as your car approaches is mathematically represented as
![f_n = f (1 + (v)/(c) )](https://img.qammunity.org/2021/formulas/physics/college/roj2hm98ndl2ua157mfa3p2s65nxn59i2s.png)
Where c is the speed of light which a has constant value of
![c = 3.0 *10^(8 ) \ m/s](https://img.qammunity.org/2021/formulas/physics/college/rw0psmop0arya3dy2ajpceo7q2nftyhwed.png)
Now
![f_n - f = (fv)/(c) )](https://img.qammunity.org/2021/formulas/physics/college/6pjl7wr8l5o0q16v6fkkw8u7i30yjz7e6x.png)
=>
substituting values
![\Delta f = ( 8.66 *10^(9) * 35)/(3.0 *10^8 )](https://img.qammunity.org/2021/formulas/physics/college/hugs865wj450mq2gd967n5fc7tfdkec0ji.png)