129k views
13 votes
how mant joules of heat energy must be added to 5 grams of liquid water to change its temperature from 10 degrees celsius ton30 degrees celsius

2 Answers

6 votes
Answer:

418

Step-by-step explanation:

A specific heat of water= 4.18 J/g.k


Q= 10(4.18)(10)

Q= 418 J
User Suresh Atta
by
5.3k points
5 votes
The answer to your question is 418
User Snehasis Ghosh
by
4.9k points