how mant joules of heat energy must be added to 5 grams of liquid water to change its temperature from 10 degrees celsius ton30 degrees celsius

asked Oct 10, 2023 129k views

13 votes

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6 votes

Answer:

418

Step-by-step explanation:

A specific heat of water= 4.18 J/g.k

Q= 10(4.18)(10)

Q= 418 J

Suresh Atta answered Oct 11, 2023

8.0k points

5 votes

The answer to your question is 418

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