Question

When using the identity for the sum of two cubes to factor 125q^6-r^6s^3

Answer 1

a=5q2 b=r2s the expression factored is also (5q2-r2s) (25q4+5q2r2s+1r4s2)

Explanation:

Answer 2

a = 5q²

b = r²s

Explanation:

The given identity is
`a^(3)-b^(3)=(a-b)(a^(2)+ab+b^(2))`

we have to use this identity to factor of two cubes given as
`125q^(6)-r^(6)s^(3)=(5q^(2))^(3)-(r^(2)s)^(3)`

As this expression is in the form of a³- b³

Here a is 5q² and b is r²s.