Answer: A) ΔBCD ≅ ΔMKL
Explanation:
In the given picture, it can be seen that
In Δ BCD and ΔMKL
∠B = ∠M
∠C = ∠K
∠D = ∠L
So, corresponding angles are equal.
Also,
segment BD = segment ML
segment DC = segment KL
segment BC = segment MK
So by using SSS (Side-Side-Side) postulate of congruence, we have
ΔBCD ≅ ΔMKL
Hence, the correct option is A) ΔBCD ≅ ΔMKL.
- SSS (Side-Side-Side) postulate of congruence says that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent